A projectile is projected at 20 ~ms ^ -1 , at its highest point where it breaks into…

Physics · JEE Main · NTA ExamsLaws of Motion

A projectile is projected at \(20 \mathrm{~ms}^{-1}\), at its highest point where it breaks into equal parts due to an internal explosion. One part moves vertically up at \(30 \mathrm{~ms}^{-4}\) with respect to the ground. Then the other part will move at
  1. \(20 \mathrm{~m} / \mathrm{s}\)
  2. \(10 \sqrt{13} \mathrm{~m} / \mathrm{s}\)
  3. \(50 \mathrm{~m} / \mathrm{s}\)
  4. \(30 \mathrm{~m} / \mathrm{s}\)

Answer

(C) 50 ~m / s

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