The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical…
Physics · JEE Advanced · NTA Exams — Rotational Motion
The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height h from rest without sliding is
- \(\sqrt{\frac{10 g h}{7}}\)
- \(\sqrt{g h}\)
- \(\sqrt{2 g h}\)
- \(\sqrt{\frac{6 g h}{5}}\)
Answer
(A) 10 g h 7
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