a f(x+1)+b f ( 1 x+1 )=x_ i x -1_ i a b , then f (2) is equal to

Mathematics · JEE Main · NTA ExamsSets, Relations and Functions

\(a f(x+1)+b f\left(\frac{1}{x+1}\right)=x_{i} x \neq-1_{i} a \neq b\), then \(\text { f (2) }\) is equal to
  1. \(\frac{2 a+b}{2\left(a^{2}-b^{2}\right)}\)
  2. \(\frac{a}{a^{2}-b^{2}}\)
  3. \(\frac{a+2 b}{a^{2}-b^{2}}\)
  4. None of these

Answer

(D) None of these

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