a f(x+1)+b f ( 1 x+1 )=x_ i x -1_ i a b , then f (2) is equal to
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
\(a f(x+1)+b f\left(\frac{1}{x+1}\right)=x_{i} x \neq-1_{i} a \neq b\), then \(\text { f (2) }\) is equal to
- \(\frac{2 a+b}{2\left(a^{2}-b^{2}\right)}\)
- \(\frac{a}{a^{2}-b^{2}}\)
- \(\frac{a+2 b}{a^{2}-b^{2}}\)
- None of these
Answer
(D) None of these
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