Function f : R → R satisfies the functional equation f(x-y)= f(x) f(y) If f’(0) = p and…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
Function f : R → R satisfies the functional equation
\(f(x-y)=\frac{f(x)}{f(y)}\)
If f’(0) = p and f’ (a ) = q, then f’ (–a) is
\(f(x-y)=\frac{f(x)}{f(y)}\)
If f’(0) = p and f’ (a ) = q, then f’ (–a) is
- \(\frac{p^{2}}{q}\)
- \(\frac{q}{p}\)
- \(\frac{p}{q}\)
- q
Answer
(A) p^ 2 q
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