The value of _ x 0 1 x^ 3 _ 0 ^ x t (1+t) t^ 4 +4 d t is
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
The value of \(\lim _{x \rightarrow 0} \frac{1}{x^{3}} \int_{0}^{x} \frac{t \ln (1+t)}{t^{4}+4} d t\) is
- 0



Answer
(B)
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