Four identical rods are joined end to end to form a square. The mass of each rod is M…
Physics · JEE Main · NTA Exams — Rotational Motion
Four identical rods are joined end to end to form a square. The mass of each rod is M. The moment of inertia of the square about the median line is: [length of each rod is L]
- \(\frac{M L^{2}}{3}\)
- \(\frac{M^{2}}{4}\)
- \(\frac{M L^{2}}{6}\)
- \(\frac{2 M L^{2}}{3}\)
Answer
(D) 2 M L^ 2 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The breaking tension of a string is 10 N. A particle of mass 0.1 kg tied to it is rotated along a horizontal…
- A particle moves along a circle of radius ( 20 ) m with constant tangential acceleration. If the velocity of…
- An automobile moves on a road with a speed of 54 km/h. The radius of its wheels is 0.45 m and the moment of…
- A particle is moving along a circular path of radius 2m with uniform speed of 5 ms –1 . What will be the…
- A particle moves in a force field given by: F = r F , where r is a unit vector along the position vector r …
- A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The…
- The ratio of the squares of radii of gyration of a circular disc and a circular ring of the same radius about…
- The linear velocity of a particle on the equator is nearly (radius of the earth is 4000 miles):
More Rotational Motion questions · Browse all practice questions