If P 1 : r n _ 1 - d 1 = 0, P 2 : r n _ 2 – d 2 = 0 and P 3 : r n _ 3 – d 3 = 0 are three…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
If P1 : \(\overrightarrow{\mathrm{r}} \cdot \overrightarrow{\mathrm{n}}_{1}-\) d1 = 0, P2 : \(\overrightarrow{\mathrm{r}} \cdot \overrightarrow{\mathrm{n}}_{2}\) – d2 = 0 and P3 : \(\overrightarrow{\mathrm{r}} \cdot \overrightarrow{\mathrm{n}}_{3}\) – d3 = 0 are three planes and \(\overrightarrow{\mathrm{n}}_{1}, \overrightarrow{\mathrm{n}}_{2}\) and \(\overrightarrow{\mathrm{n}}_{3}\) are three non–coplanar vectors then, the three lines P1=0, P2=0 and
P2=0, P3=0 and P3 = 0, P1 = 0 are
P2=0, P3=0 and P3 = 0, P1 = 0 are
- parallel lines
- coplanar lines
- coincident lines
- concurrent lines
Answer
(D) concurrent lines
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