Equation of line in the plane P : 2x – y + z – 4 = 0 which is perpendicular to the line l…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
Equation of line in the plane P : 2x – y + z – 4 = 0 which is perpendicular to the line l whose equation is \(\frac{x-2}{1}=\frac{y-2}{-1}=\frac{z-3}{-2}\) and which passes through the point of intersection of l and P is
- \(\frac{x-2}{3}=\frac{y-1}{5}=\frac{z-1}{-1}\)
- \(\frac{x-1}{3}=\frac{y-3}{5}=\frac{z-5}{-1}\)
- \(\frac{x+2}{2}=\frac{y+1}{-1}=\frac{z+1}{1}\)
- \(\frac{x-2}{2}=\frac{y-1}{-1}=\frac{z-1}{1}\)
Answer
(B) x-1 3 = y-3 5 = z-5 -1
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