The equation of a plane passing through the line of intersection of the planes x + 2 y +…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
The equation of a plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x – y + z = 3
and at a distance \(\frac{2}{\sqrt{3}}\) from the point (3, 1, –1) is
and at a distance \(\frac{2}{\sqrt{3}}\) from the point (3, 1, –1) is
- 5x – 11y + z = 17
- \(\sqrt{2} x+y=3 \sqrt{2}-1\)
- \(x+y+z=\sqrt{3}\)
- \(x-\sqrt{2} y=1-\sqrt{2}\)
Answer
(A) 5 x – 11 y + z = 17
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