If a plane cuts off intercepts OA = a, OB = b, OC = c from the coordinate axes, then the…

Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry

If a plane cuts off intercepts OA = a, OB = b, OC = c from the coordinate axes, then the area of the triangle ABC =

\(\frac{1}{2} \sqrt{b^{2} c^{2}+c^{2} a^{2}+a^{2} b^{2}}\)
\(\frac{1}{2}(b+a+b)\)
\(\frac{1}{2} \mathrm{abc}\)
\(\frac{1}{2} \sqrt{(\mathrm{~b}-\mathrm{c})^{2}+(\mathrm{c}-\mathrm{a})^{2}+(\mathrm{a}-\mathrm{b})^{2}}\)

Answer

(A) 1 2 b^ 2 c^ 2 +c^ 2 a^ 2 +a^ 2 b^ 2

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.