A, B, C and D are four points in a plane with pv ^ s a , ~b , c and d respectively such…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
A, B, C and D are four points in a plane with \(\mathrm{pv}^{\prime} \mathrm{s} \overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{~b}}, \overrightarrow{\mathrm{c}} \text { and } \overrightarrow{\mathrm{d}}\)respectively such that
\((\vec{a}-\vec{d}) \cdot(\vec{b}-\vec{c})=(\vec{b}-\vec{d}) \cdot(\vec{c}-\vec{a})=0\).
Then for the triangle ABC, D is its :
\((\vec{a}-\vec{d}) \cdot(\vec{b}-\vec{c})=(\vec{b}-\vec{d}) \cdot(\vec{c}-\vec{a})=0\).
Then for the triangle ABC, D is its :
- incentre
- circumcentre
- othocentre
- centroid
Answer
(C) othocentre
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