A wheel of mass M and radius a and Moment of inertia IG (about centre of mass) is set…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A wheel of mass M and radius a and Moment of inertia IG (about centre of mass) is set rolling with angular velocity w up a rough inclined plane of inclination q. The distance travelled by it up the plane is:
- \(\frac{I_{G} \omega^{2}}{2 m g \sin \theta}\)
- \(\frac{\omega^{2}\left(M t^{2}+I_{G}\right)}{2 M g \sin \theta}\)
- \(\frac{I_{G} \omega^{2}}{2 \omega M g \sin \theta}\)
- \(\frac{I_{g} \omega}{2 M g \sin \theta}\)
Answer
(B) ^ 2 (M t^ 2 +I_ G ) 2 M g
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