Starting at time t = 0 from the origin with speed 1 m s −1 , a particle follows a…
Physics · JEE Advanced · NTA Exams — Kinematics
Starting at time t = 0 from the origin with speed
1 m s−1, a particle follows a two-dimensional trajectory in the x-y plane so that its coordinates are related by the equation \(y=\frac{x^{2}}{2} .\) The x and y components of its acceleration are denoted by ax and ay, respectively. Then
1 m s−1, a particle follows a two-dimensional trajectory in the x-y plane so that its coordinates are related by the equation \(y=\frac{x^{2}}{2} .\) The x and y components of its acceleration are denoted by ax and ay, respectively. Then
- ax =1 m s−2 implies that when the particle is at the origin, ay = 1 m s−2
- ax = 0 implies ay = 1 m s−2 at all times
- at t = 0, the particle’s velocity points in the x-direction
- ax = 0 implies that at t =1 s, the angle between the particle’s velocity and the x axis is 45°.
Answer
(C) at t = 0, the particle’s velocity points in the x -direction
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