The number of real roots of the equation ^ -1 x(x+1) + ^ -1 x^ 2 +x+1 = 4 is
Physics · JEE Main · NTA Exams — Kinematics
The number of real roots of the equation
\(\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{4} \text { is }\)
\(\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{4} \text { is }\)
- 2
- 0
- 4
- 1
Answer
(D) 1
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