The suitable expression for the equilibrium constant of the reaction 2NO (g) + C l 2 (g)…
Chemistry · JEE Main · NTA Exams — Equilibrium
The suitable expression for the equilibrium constant of the reaction 2NO (g) + Cl2(g) \(\text { ⇌ }\) 2NOCl (g) is
- \(\mathrm{K}_{\mathrm{c}}=\frac{[2 \mathrm{NOCl}]}{[2 \mathrm{NO}]\left[\mathrm{Cl}_{2}\right]}\)
- \[\mathrm{K}_{\mathrm{c}}=\frac{[\mathrm{NOCl}]^{2}}{[\mathrm{NO}]^{2}\left[\mathrm{Cl}_{2}\right]}\]
- \(\mathrm{K}_{\mathrm{c}}=\frac{[\mathrm{NOCl}]^{2}}{[\mathrm{NO}]\left[\mathrm{Cl}_{2}\right]^{2}}\)
- \(\mathrm{K}_{\mathrm{c}}=\frac{[\mathrm{NOCl}]^{2}}{[\mathrm{NO}]^{2}\left[\mathrm{Cl}_{2}\right]^{2}}\)
Answer
(B) K _ c = [ NOCl ]^ 2 [ NO ]^ 2 [ Cl _ 2 ]
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