If 0 x 1+x^ 2 [ x ( ^ -1 x )+ ( ^ -1 x ) ^ 2 -1 ]^ 1 / 2 =
Mathematics · JEE Advanced · NTA Exams — Trigonometry
If 0 < x < 1, then
\(\sqrt{1+x^{2}}\left[\left\{x \cos \left(\cot ^{-1} x\right)+\sin \left(\cot ^{-1} x\right)\right\}^{2}-1\right]^{1 / 2}=\)
\(\sqrt{1+x^{2}}\left[\left\{x \cos \left(\cot ^{-1} x\right)+\sin \left(\cot ^{-1} x\right)\right\}^{2}-1\right]^{1 / 2}=\)
- x
Answer
(B) x
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