The no. of real solutions of ^ -1 x(x+1) + ^ -1 x^ 2 +x+1 = 2 is
Mathematics · JEE Advanced · NTA Exams — Trigonometry
The no. of real solutions of
\(\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{2}\) is
\(\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{2}\) is
- zero
- one
- two
- infinite
Answer
(B) one
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