A particle moves under a force F = Cx from x = 0 to x = x 1 . The work done is:
Physics · JEE Main · NTA Exams — Work, Energy and Power
A particle moves under a force F = Cx from x = 0 to x = x1. The work done is:
- \(C x_{1}^{2}\)
- \(\frac{C x_{1}^{2}}{2}\)
- 0
- \(C x_{i}^{3}\)
Answer
(B) C x_ 1 ^ 2 2
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