Under the action of a force, a 2 kg body moves such that its position x as a function of…
Physics · JEE Main · NTA Exams — Work, Energy and Power
Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x = \(\frac{t^{3}}{3}\), where x is in metre and t in second. The work done by the force in the first two seconds is:
- 1600 J
- 160 J
- 16 J
- 1.6 J
Answer
(C) 16 J
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