If the inequality (m-2) x^ 2 +8 x+m+4>0 is satisfied for all x R then the least integral…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If the inequality \((m-2) x^{2}+8 x+m+4>0\) is satisfied for all \(x \in R\) then the least integral m is:
- \(4\)
- \(5\)
- \(6\)
- \(-5\)
Answer
(B) 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The equation b z+b z =c where b is a non zero complex constant and c is real, represents
- The roots of the equation |x 2 – x – 6| = x + 2 are
- The roots of the quadratic equation 7x 2 – 9x + 2 = 0 are
- For any two complex numbers z 1 and z 2 and any real numbers a and b; |(az 1 – bz 2 )| 2 + |(bz 1 + az 2 )| 2…
- If ω is a cube root of unity, then (3 + 5ω + 3ω 2 ) 2 + (3 + 3ω + 5ω 2 ) 2 is equal to
- Let z, w be complex numbers such that z +i w =0 and arg (zw) = π. Then, arg (z) equals
- i^ 2 +i^ 4 +i^ 6 + upto (2 k+1) terms, k N is
- If the sum of the squares of the roots of the equation x^ 2 -( x-2) x-(1+ x)=0 is least, then II is
More Complex Numbers and Quadratic Equations questions · Browse all practice questions