_ 0 ^ 2 e^ | x| x 1+e^ x d x=
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\int_{0}^{2 \pi} \frac{e^{|\sin x|} \cos x}{1+e^{\tan x}} d x=\)
- \(e^{\pi}\)
- \(1\)
- \(e^{\pi}-1\)
- \(0\)
Answer
(D) 0
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