Two circles x 2 + y 2 = 6 and x 2 + y 2 – 6x + 8 = 0 are given. Then the equation of the…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
Two circles x2 + y2 = 6 and x2 + y2 – 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is :
- x2 + y2 – 6x + 4 = 0
- x2 + y2 – 3x + 1 = 0
- x2 + y2 – 4y + 2 = 0
- none of these
Answer
(B) x 2 + y 2 – 3x + 1 = 0
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