The rate law for the reaction: R Cl + NaOH ( aq ) → R OH + NaCl is given by, Rate = k [ R…
Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics
The rate law for the reaction:
RCl + NaOH(aq)→ ROH + NaCl is given by,
Rate = k [RCl]. The rate of the reaction will be
RCl + NaOH(aq)
Rate = k [RCl]. The rate of the reaction will be
- doubled on doubling the concentration of sodium hydroxide
- halved on reducing the concentration of alkyl halide to one half
- increased on increasing the temperature of the reaction
- unaffected by increasing the temperature of the reaction.
Answer
(C) increased on increasing the temperature of the reaction
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Two gases A and B are filled in a container. The experimental rate law for the reaction between them, has…
- Plots showing the variation of the rate constant ( k ) with temperature ( T ) are given below. The plot that…
- The equilibrium constant of reaction is 20.0 At equilibrium, the rate constant of forward reaction is 10.0…
- The rate of a reaction at different times (- d d ) is found as follows : Time (in minute) Rate in (mol L –1 s…
- For the following reaction 2 X + Y k P the rate of reaction is d [ P ] dt = k [ X ] . Two moles of X are…
- Estrification of acetic anhydride by ethanol takes place as (CH 3 CO) 2 O + C 2 H 5 OH → CH 3 COOC 2 H 5 + CH…
- The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at 25 °C are…
- Consider an endothermic reaction X → Y with the activation energies E b and E f for the backward and forward…
More Chemical Kinetics questions · Browse all practice questions