Estrification of acetic anhydride by ethanol takes place as (CH 3 CO) 2 O + C 2 H 5 OH →…
Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics
Estrification of acetic anhydride by ethanol takes place as
(CH3CO)2 O + C2H5OH → CH3COOC2H5 + CH3COOH
Select the correct statements of the following :
(CH3CO)2 O + C2H5OH → CH3COOC2H5 + CH3COOH
Select the correct statements of the following :
- When reaction is carried out in dilute hexane solution, the rate law is given by k [Anhydride] [Alcohol]
- When ethanol is the solvent, the rate law is given by k [Anhydride]
- The values of k in the two cases are the same
- Using ethanol as the solvent, its concentration changes significantly during the course of the reaction
Answer
(A) When reaction is carried out in dilute hexane solution, the rate law is given by k [Anhydride] [Alcohol], (B) When ethanol is the solvent, the rate law is given by k [Anhydride]
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