If 6 cos 2θ + 2 cos 2 ( 2 ) + 2 sin 2 θ = 0, – π θ =
Mathematics · JEE Advanced · NTA Exams — Trigonometry
If 6 cos 2θ + 2 cos2\(\left(\frac{\theta}{2}\right)\) + 2 sin2 θ = 0, – π < θ < π, then
θ =
θ =
- π/6
- π /3, cos–1 (3/5)
- cos–1 (3/5)
- π /3, π – cos–1 (3/5)
Answer
(D) π /3, π – cos –1 (3/5)
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