A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to…
Physics · JEE Advanced · NTA Exams — Kinetic Theory of Gases
A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to 0°C. If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than radius of the earth. (kB is Boltzmann constant)
- \(\frac{273 \mathrm{k}_{\mathrm{B}}}{2 \mathrm{Mg}}\)
- \(\frac{546 \mathrm{k}_{\mathrm{R}}}{3 \mathrm{Mg}}\)
- 0
- \(\frac{819 \mathrm{k}_{\mathrm{p}}}{2 \mathrm{Mg}}\)
Answer
(D) 819 k _ p 2 Mg
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