A monoatomic gas undergoes a cyclic process as shown in the figure. The ideal gas follows…
Physics · JEE Advanced · NTA Exams — Kinetic Theory of Gases
A monoatomic gas undergoes a cyclic process as shown in the figure. The ideal gas follows the equation T = bV2 for the process B → C. During the cycle; the ratio of maximum to minimum pressure is 2 and heat supplied to the gas in B → C is QB → C = 120 J. Assuming usual meanings for the symbols, pick correct option(s)
- PA = PC
- \(\frac{T_{A}}{T_{B}}=2\)
- \(\frac{T_{c}}{T_{B}}=2\)
- QC → A → B = –130J
Answer
(A) P A = P C, (B) T_ A T_ B =2, (D) Q C → A → B = –130J
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