A train approaches a stationary observer, the velocity of train being 1 20 of the…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A train approaches a stationary observer, the velocity of train being \(\frac{1}{20}\) of the velocity of sound. A sharp blast is blown with the whistle of the engine at equal intervals of a second. The interval between the successive blasts as heard by the observer is:
- \(\frac{1}{20}\)s
- \(\frac{1}{20}\)min
- \(\frac{19}{20} s\)
- \(\frac{19}{20} \mathrm{~min}\)
Answer
(C) 19 20 s
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A string of 5.5 m length has a mass 0.035 kg. If the tension in the string is 77 N, then the speed of wave on…
- Match the following columns of damped oscillations expressed by x(t)=A e^ -b t / 2 m ( ^ t+ ) , where…
- The graph between velocity and position for a damped oscillation will be:
- A block is in SHM on a frictionless surface as shown in the figure. The position x = 0 shows the unstretched…
- A body is moving in a room with a velocity of 20 m/s perpendicular to the two walls separated by 5 m. There…
- A wave frequency 100 Hz is sent along a string towards a fixed end. When this wave travels back, after…
- A man measures time period of a simple pendulum inside a stationary lift and find it to be T. If the lift…
- Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave…
More Oscillations and Waves questions · Browse all practice questions