A man measures time period of a simple pendulum inside a stationary lift and find it to…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A man measures time period of a simple pendulum inside a stationary lift and find it to be T. If the lift starts accelerating upwards with an acceleration g/4, then the time period of pendulum will be
- \(\frac{2 T}{\sqrt{5}}\)
- \(\frac{\sqrt{5} T}{2}\)
- \(\frac{\sqrt{5}}{2 T}\)
- \(\frac{2}{\sqrt{5} T}\)
Answer
(A) 2 T 5
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