A body of mass 2 kg is moving along X direction with velocity 2 m/s. If a force of 4 N is…
Physics · NEET · NTA Exams — Kinematics
A body of mass 2 kg is moving along X direction with velocity 2 m/s. If a force of 4 N is applied on it along Y direction for 1 s, then the final velocity of the body will be
- \(2 \sqrt{2} \mathrm{~m} / \mathrm{s}\)
- \(\sqrt{2} \mathrm{~m} / \mathrm{s}\)
- \(\frac{1}{\sqrt{2}} \mathrm{~m} / \mathrm{s}\)
- \(\frac{1}{2 \sqrt{2}} \mathrm{~m} / \mathrm{s}\)
Answer
(A) 2 2 ~m / s
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