Let A= E (- 2 , ): 3+2 i 1-2 i is purely imaginary . Then the sum of the elements in A is:
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
Let \(A=\left\{\theta E\left(-\frac{\pi}{2}, \pi\right): \frac{3+2 i \sin \theta}{1-2 i \sin \theta} \text { is purely imaginary }\right\}\). Then the sum of the elements in A is:
- \(\frac{5 \pi}{6}\)
- \(\frac{3 \pi}{4}\)
- \(\frac{2 \pi}{3}\)
- \(\text { TL }\)
Answer
(C) 2 3
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