A car is moving with a speed v on a road inclined at an angle θ in a circular arc of…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A car is moving with a speed v on a road inclined at an angle θ in a circular arc of radius r, the minimum coefficent of friction so that the car does not slip away-
- \(\frac{\mathrm{v}^{2}}{\mathrm{rg}}\)= µ tan θ
- \(\mu=\frac{\mathrm{v}^{2}}{\mathrm{rg}}\)
- \(\frac{v^{2} \cos \theta-r g \sin \theta}{r g \cos \theta+v^{2} \sin \theta}\)
- \(\frac{\mathrm{v}^{2} \cos \theta-\mathrm{rg} \sin \theta}{\mathrm{rg} \cos \theta-\mathrm{v}^{2} \sin \theta}\)
Answer
(C) v^ 2 -r g r g +v^ 2
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