If the system of equations x + y + z = 6, x + 2y + 3z = 10 and x + 2y + λ z = µ has no…
Mathematics · JEE Main · NTA Exams — Matrices and Determinants
If the system of equations x + y + z = 6, x + 2y + 3z = 10 and x + 2y + λ z = µ has no solution, then the values of λ and µ are
- λ = 3, µ = 10
- λ = 3, µ ≠ 10
- λ ≠ 3, µ = 10
- λ ≠ 3, µ ≠ 10
Answer
(B) λ = 3, µ ≠ 10
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