If the equations z x-y+z z=z x-2 y+z=-4 x+y+ z=4 have no solution, then the value of will…
Mathematics · JEE Main · NTA Exams — Matrices and Determinants
If the equations
\(z x-y+z z=z\)
\(x-2 y+z=-4\)
\(x+y+\lambda z=4\)
have no solution, then the value of \(\lambda\) will be
- \(1\)
- \(2\)
- \(3\)
- \(-4\)
Answer
(B) 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The number of real values of for which the system of linear equations array l 2 x+4 y- z=0 4 x+ y+2 z=0 x+2…
- If i = t 2 for 0 < t < T, then r.m.s. value of current is :
- If A= [ array ll a & b b & a array ] and A^ 2 = [ array ll x & & x array ] , then
- STATEMENT - 1: A= [ array lll 4 & 0 & 4 2 & 3 & 2 1 & 2 & 1 array ], B= [ array lll 1 & 3 & 3 1 & 4 & 3 1 & 3…
- If A, B, C are matrices of order 1 × 3, 3 × 3 and 3 × 1 respectively, the order of ABC will be -
- Let A be a square matrix of order n x n and K be a scalar. Then |KA| equals
- The number of values of θ (0, π) for which the system of linear equations array l x+3 y+7 z=0 -x+4 y+7 z=0 (…
- If A is an 3 3 non-singular matrix such that A^ =A^ A and B=A^ -1 A^ , then BB' equals :
More Matrices and Determinants questions · Browse all practice questions