A pendulum consists of a wooden bob of mass m and of lenght l . A bullet of mass m 1 is…
Physics · JEE Advanced · NTA Exams — Laws of Motion
A pendulum consists of a wooden bob of mass m and of lenght l. A bullet of mass m1 is fired towards the pendulum with a speed v1. The bullet emerges out of the bob with a speed v1/3 and the bob just completes motion along a vertical circle. Then v1 is
- \(\left(\frac{\mathrm{m}}{\mathrm{~m}_{1}}\right) \sqrt{5 \mathrm{~g} \ell}\)
- \(\frac{3}{2}\left(\frac{\mathrm{~m}}{\mathrm{~m}_{1}}\right) \sqrt{5 \mathrm{~g} \ell}\)
- \(\frac{2}{3}\left(\frac{\mathrm{~m}_{1}}{\mathrm{~m}}\right) \sqrt{5 \mathrm{~g} \ell}\)
- \(\left(\frac{\mathrm{m}_{1}}{\mathrm{~m}}\right) \sqrt{\mathrm{g} \ell}\)
Answer
(B) 3 2 ( ~m ~m _ 1 ) 5 ~g
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