The position of a particle moving along X-axis is given by the equation x = [a t^ 2 +b…
Physics · JEE Main · NTA Exams — Physics and Measurement
The position of a particle moving along X-axis is given by the equation \(\mathbf{x}=\left[a t^{2}+b t+c\right] \text { metre }\). The dimensions of a, b and c are respectively
- \(\mathrm{LT}^{-2}, \mathrm{LT}^{-1}, \mathrm{~L}\)
- \(\mathrm{L}, \mathrm{LT}^{-1}, \mathrm{LT}^{-2}\)
- \(\mathrm{LT}^{-2}, \mathrm{LT}, \mathrm{~L}\)
- \(\mathrm{LT}^{-2}, \mathrm{~L}_{1} \mathrm{LT}^{-2}\)
Answer
(A) LT ^ -2 , LT ^ -1 , ~L
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