The current voltage relation of diode is given by I= (e^ 1000 ~V ~T -1 ) mA where the…
Physics · JEE Main · NTA Exams — Physics and Measurement
The current voltage relation of diode is given by \(I=\left(e^{1000 \frac{\mathrm{~V}}{\mathrm{~T}}}-1\right) \mathrm{mA}\) where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring \(\pm 0.01 \mathrm{~V}\) while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?
- 0.2 mA
- 0.02 mA
- 0.5 mA
- 0.05 mA
Answer
(B) 0.02 mA
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The x and y components of a force are 2 N and –3N. The force is
- If F = 6πη a r b v c where F = viscous force η = coeffficient of viscosity r = radius of spherical body v =…
- Two wires of the same material and same mass are stretched by the same force. Their lengths are in the ratio…
- In the equation y = a sin(ωt + kx), the dimensional formula of ω is
- If S = 1 3 f t 3 , where S is displacement and t is time then find the dimension of f.
- The dimension of resistance is same as that of ..... where h is the Planck's constant, e is the charge.
- The simple sum of two co-initial vectors is 16 units. Their vectors sum is 8 units. The resultant of the…
- The time dependence of a physical quantity P is given by P =P_ 0 e^ - t^ 2 where α is a constant and t is…
More Physics and Measurement questions · Browse all practice questions