The moment of inertia of a solid sphere about an axis passing through centre of gravity…
Physics · JEE Main · NTA Exams — Rotational Motion
The moment of inertia of a solid sphere about an axis passing through centre of gravity is \(\frac{2}{5} M R^{2}\); then its radius of gyration about a parallel axis at a distance 2R from first axis is:
- 5R
- \(\sqrt{\frac{22}{5}} R\)
- \(\frac{5}{2} R\)
- \(\sqrt{\frac{12}{5}} R\)
Answer
(B) 22 5 R
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A uniform rod of mass M and length L lies radially on a disc rotating with angular speed ω in a horizontal…
- A particle moves along a circle of radius ( 20 ) m with constant tangential acceleration. If the velocity of…
- A motor - cycle is moving in a vertical circular path. At what stage will the speed of the motor cycle be…
- The moment of inertia of a body about a given axis is 2.4 kg-m 2 to produce a rotational kinetic energy of…
- A sphere of mass m rolls without slipping on an inclined plane of inclination θ. The linear acceleration of…
- One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moments of…
- A particle moves in circular path with uniform speed v. The change in its velocity on rotating through 60º is…
- Figure shows a uniform rod of length l and mass M which is pivoted at end A such that it can rotate in a…
More Rotational Motion questions · Browse all practice questions