A uniform rod of mass M and length L lies radially on a disc rotating with angular speed…
Physics · JEE Main · NTA Exams — Rotational Motion
A uniform rod of mass M and length L lies radially on a disc rotating with angular speed ω in a horizontal plane about its axis. The rod does not slip on the disc and the centre of the rod is at a distance R from the centre of the disc. Then the kinetic energy of the rod is:
- \(\frac{1}{2} M \omega^{2}\left(R^{2}+\frac{L^{2}}{12}\right)\)
- \(\frac{1}{2} M \omega^{2} R^{2}\)
- \(\frac{1}{24} M \omega^{2} L^{2}\)
- none of these
Answer
(A) 1 2 M ^ 2 (R^ 2 + L^ 2 12 )
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