A car is travelling with linear velocity v on a circular road of radius r. If it is…
Physics · JEE Main · NTA Exams — Rotational Motion
A car is travelling with linear velocity v on a circular road of radius r. If it is increasing it speed at the rate of ‘a’ metre/sec2, then the resultant acceleration will be-
- \[\sqrt{\left(\frac{v^{2}}{r^{2}}-a^{2}\right)}\]
- \[\sqrt{\left(\frac{v^{4}}{r^{2}}+a^{2}\right)}\]
- \[\sqrt{\left(\frac{v^{4}}{r^{2}}-a^{2}\right)}\]
- \[\sqrt{\left(\frac{v^{2}}{r^{2}}+a^{2}\right)}\]
Answer
(B) ( v^ 4 r^ 2 +a^ 2 )
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