Standing waves are produced by the superposition of two waves y1 = 0.05 sin (3t – 2x) and…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
Standing waves are produced by the superposition of two waves y1 = 0.05 sin (3t – 2x) and
y2 = 0.05 sin (3t + 2x) where x and y are expressed in metres and t is in seconds. What is the amplitude of a particle at x = 0.5 m. Given cos (57.30) = 0.54
y2 = 0.05 sin (3t + 2x) where x and y are expressed in metres and t is in seconds. What is the amplitude of a particle at x = 0.5 m. Given cos (57.30) = 0.54
- 2.7 cm
- 5.4 cm
- 8.1 cm
- 10.8 cm
Answer
(B) 5.4 cm
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