Let h ( x ) = min x , x 2 for every real number of x . Then
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
Let h (x) = min {x, x2} for every real number of x. Then
- h is continuous for all x
- h is differentiable for all x
- h
- h is not differentiable at two values of x.
Answer
(D) h is not differentiable at two values of x .
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let y = x 3 – 8x + 7 and x = f (t). If dy dt = 2 and x = 3 at t = 0, then dx dt at t = 0 is given by
- Let g ( x ) = x f ( x ), where f(x)= array cl x 1 x , & x 0 0, & x=0 array . At x=0 .
- x 0 Limit ^ -1 ( x)
- Let f : (0, ∞) → R and F(x)= _ 0 ^ x f(t) d t If , then f (4) equals
- Let and be functions defined by f ( x ) = [ x 2 – 3] and g ( x ) = | x | f ( x ) + |4 x – 7| f ( x ), where […
- by appropriately matching the information given in the three columns of the following table. Let f ( x ) = x…
- _ n 1^ p +2^ p +3^ p + +n^ p n^ p+1 is
- Limit _ x 5 x^ 2 -9 x+20 x-[x] where [x] is the greatest integer not greater than x
More Limit, Continuity and Differentiability questions · Browse all practice questions