The solution of the differential equation d y d x + 1+x^ 2 x =0 is
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation \(\frac{d y}{d x}+\frac{1+x^{2}}{x}=0\) is
- \(y=-\frac{1}{2} \tan ^{-1} x+c\)
- \(y+\log x+\frac{x^{2}}{2}+c=0\)
- \(y=\frac{1}{2} \tan ^{-1} x+c\)
- \(y-\log x-\frac{x^{2}}{2}=c\)
Answer
(B) y+ x+ x^ 2 2 +c=0
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