The standard enthalpy of formation of H 2 (g), Cl 2 (g) and HCl (g) are 218 kJ mol -1 …
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
The standard enthalpy of formation of H2(g), Cl2(g) and HCl (g) are 218 kJ mol-1, 121.68 kJ mol-1 and - 92.31 kJ mol-1, respectively. Calculate the standard enthalpy change in kJ for:
\(\frac{1}{2}\)H2(g) + \(\frac{1}{2}\)Cl2(g) \(\text { → }\) HCl(g)
- + 431.99
- - 262.15
- - 431.99
- + 247.37
Answer
(B) - 262.15
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