Calculate the enthalpy of vaporization for water from the following:

H₂(g) + \(\frac{1}{2} O_{2}(g)\) → H₂O (g), ∆H = - 57.0 kcal mol^-1

H₂ (g) + \(\frac{1}{2} O_{2}(g)\) → H₂O (l), ∆H = - 68.3 kcal mol^-1

Question

Calculate the enthalpy of vaporization for water from the following: H 2 (g) + 1 2 O_ 2 (g) → H 2 O (g), ∆H = - 57.0 kcal mol -1 H 2 (g) + 1 2 O_ 2 (g) → H 2 O (l), ∆H = - 68.3 kcal mol -1

Accepted Answer

(B) 11.3 kcal mol -1

Calculate the enthalpy of vaporization for water from the following: H 2 (g) + 1 2 O_ 2…

Answer

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