If f (x) = x-1 x+1 , then f (2x) is :
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
If f (x) = \(\frac{x-1}{x+1}\), then f (2x) is :
- \(\frac{f(\mathrm{x})+1}{f(\mathrm{x})+3}\)
- \(\frac{3 f(\mathrm{x})+1}{f(\mathrm{x})+3}\)
- \(\frac{f(\mathrm{x})+3}{f(\mathrm{x})+1}\)
- \(\frac{f(\mathrm{x})+3}{3 f(\mathrm{x})+1}\)
Answer
(B) 3 f( x )+1 f( x )+3
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