If f is an even function defined on the interval (–5, 5) then a value of x satisfying the…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
If f is an even function defined on the interval (–5, 5) then a value of x satisfying the equation f (x) = f \(\left(\frac{x+1}{x+2}\right)\) is
- \(\frac{-1+\sqrt{5}}{2}\)
- \(\frac{-3+\sqrt{5}}{2}\)
- \(\frac{-1-\sqrt{5}}{2}\)
- \(\frac{-3-\sqrt{5}}{2}\)
Answer
(A) -1+ 5 2, (B) -3+ 5 2, (C) -1- 5 2, (D) -3- 5 2
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