If the straight line ax + by = 2, b ≠ 0, touches the circle x 2 + y 2 – 2x = 3 and is…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
If the straight line ax + by = 2, b ≠ 0, touches the circle
x2 + y2 – 2x = 3 and is normal to the circle x2 + y2 – 4y = 6, then the values of a and b can be
x2 + y2 – 2x = 3 and is normal to the circle x2 + y2 – 4y = 6, then the values of a and b can be
- a = 1, b = 2
- a = 1, b = –1
- a = –4/3, b = 1
- None of these
Answer
(C) a = –4/3, b = 1
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