The equilibrium concentration of X, Y and YX 2 are 4, 2 and 2 M respectively for the…
Chemistry · JEE Main · NTA Exams — Equilibrium
The equilibrium concentration of X, Y and YX2 are 4, 2 and 2 M respectively for the equilibrium
2X + Y \(\text { ⇌ }\) YX2. The value of Kc is
2X + Y \(\text { ⇌ }\) YX2. The value of Kc is
- 0.625
- 0.0625
- 6.25
- 0.00625
Answer
(B) 0.0625
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