A uniform rod of length L is free to rotate in a vertical plane about a fixed horizontal…
Physics · JEE Main · NTA Exams — Rotational Motion
A uniform rod of length L is free to rotate in a vertical plane about a fixed horizontal axis through B. The rod begins rotating from rest from its unstable equilibrium position. When it has turned through an angle θ its average angular velocity ω is given as:
- \(\sqrt{\frac{6 g}{L}} \sin \theta\)
- \(\sqrt{\frac{6 g}{L}} \sin \frac{\theta}{2}\)
- \(\sqrt{\frac{6 g}{L}} \cos \frac{\theta}{2}\)
- \(\sqrt{\frac{6 g}{L}} \cos \theta\)
Answer
(B) 6 g L 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- An electric motor operates at 20 rev/s. What will be the approximate power delivered by the motor if it…
- A ground stone has a moment of inertia of 600 kg-m 2 . A constant torque is applied and the ground stone is…
- What happens to centripital force of a revolving body if you double the orbital speed v and halve the angular…
- An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction . A…
- A string can bear a maximum tension of 100 Newton without breaking. A body of mass 1 kg is attached to one…
- A hoop rolls on a horizontal ground without slipping with linear speed v. Speed of a particle P on the…
- A flywheel of mass 50 kg and radius of gyration about its axis of rotation of 0.5m is acted upon by a…
- A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The…
More Rotational Motion questions · Browse all practice questions